The leangth of rectangle is 10m more than its breadth. If the perimeter of rectangle is 80m, Find the dimensions of the rectangle.
Answers
The perimeter of an object is the sum of all it's lengths. So in this problem, 80m = side1 + side2 + side3 + side4.
Now a rectangle has 2 sets of equal length sides.
So 80m = 2xSide1 + 2xSide2
And we are told that the length is 10m more than it's breadth.
So 80m = 2xSide1+(10+10) + 2xSide2
So 80m = 2xS1+20 +2S2
80 = 2x + 2y + 20
If it were a square, x + y would be the same
so
60 = 4x side1
so side 1 = 60/4 = 15m
So side 1 = 15m, side 2 = 15m, side 3 = 15m+10m side 4 = 15+10m
So s1 = 15m, s2 = 15m, s3 = 25m, s4 = 25m.
Perimiter = 80m and the length of th e rectangle is 10m longer than the breadth
Answer:
The length of a rectangle is 10 m more than its bredth. if the perimeter of rectangle is 80 m . find the demensions of rectangle.
Length [l]
Breadth [B]
Length of a rectangle is 10 m more than its breadth
So , if we let unknown breadth be "x"
Then our length will become ( x + 10 )
❥ Perimeter of Rectangle ↠ 80m
❥ What's the Dimensions of Rectangle ?
Here we go !
As we know ,
Perimeter of Rectangle = 2( L + B )
Now,
As according to given
↠ Perimeter of Rectangle = 2 ( x + x + 10)
↠ 80 = 2 ( 2x + 10 )
↠ 80/2 = 2x + 10
↠ 40 = 2x + 10
↠ 2x = 30
↠ x = 15.
Hence,
The Value of x is 15
Therefore,
↠ Length
↠ x + 10
↠ 15 + 10 ↠ 25
↠ Breadth = x = 15.
Additional Information :-
❥ Perimeter of Rectangle = 2( L + B )
❥ Perimeter of square = 4 × Side
❥ Perimeter of triangle = AB + BC + CA
❥ Area of Rectangle = L × B
❥ Area of Square = ( side ) ²
❥ Area of Rhombus = Product of Diagonal/2.
❥ Area of Parallelogram = Base × Height.
❥ Area of triangle = 1/2 × base × height .