Question

The leangth of rectangle is 10m more than its breadth. If the perimeter of rectangle is 80m, Find the dimensions of the rectangle.​
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Answer 1

Question :-

The length of a rectangle is 10 m more than its bredth. if the perimeter of rectangle is 80 m . find the demensions of rectangle.

Answer.

$\red{\bigstar}$ Length [l]

$\huge\leadsto{\sf\purple{25 \: m}}$

$\red{\bigstar}$ Breadth [B]

$\huge\leadsto{\sf\purple{15 \: m}}$

Given :-

Length of a rectangle is 10 m more than its breadth

So , if we let unknown breadth be "x"

Then our length will become ( x + 10 )

❥ Perimeter of Rectangle ↠ 80m

Find :-

❥ What's the Dimensions of Rectangle ?

Solution :-

Here we go !

As we know ,

Perimeter of Rectangle = 2( L + B )

Now,

As according to given

↠ Perimeter of Rectangle = 2 ( x + x + 10)

↠ 80 = 2 ( 2x + 10 )

↠ 80/2 = 2x + 10

↠ 40 = 2x + 10

↠ 2x = 30

↠ x = 15.

Hence,

The Value of x is 15

$\therefore\underline{\boxed{\textsf{The value of x is = {\textbf{15}}}}} \qquad\qquad \bigg\lgroup\bold{Correct \ answer} \bigg\rgroup$

Therefore,

↠ Length

↠ x + 10

↠ 15 + 10 ↠ 25

↠ Breadth = x = 15.

Additional Information :-

❥ Perimeter of Rectangle = 2( L + B )

❥ Perimeter of square = 4 × Side

❥ Perimeter of triangle = AB + BC + CA

❥ Area of Rectangle = L × B

❥ Area of Square = ( side ) ²

❥ Area of Rhombus = Product of Diagonal/2.

❥ Area of Parallelogram = Base × Height.

❥ Area of triangle = 1/2 × base × height .

_______________________

Answer 2

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Appropriate~question :-}}}}}}$

The leangth of rectangle is 10m more than its breadth. If the perimeter of rectangle is 80m, Find the dimensions of the rectangle.

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Required~Answer :-}}}}}}$

length - $\bf{\orange{25m}}$

breadth - $\bf{\orange{15m}}$

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

⠀⠀perimeter of rectangle = $\bf{\orange{80m}}$

$\sf{\bold{\green{\underline{\underline{find}}}}}$

What's the dimension of rectangle ?

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

$\boxed {\sf {\pink { perimeter~of~rectangle~=~2(l+b)}}}$

Now ,

As according to given -

perimeter of rectangle ☆ $2(x+x+10)$

☆ $80 = 2(2x+10)$

☆ $80 / 2 = 2x + 10$

☆ $40 = 2x + 10$

☆ $2x = 30$

☆ $x = 15$

$\orange{\sf{\star\;Hence}}$

$\boxed {\sf {\red { The~value~of~x~is~15}}}$ correct answer

${ \bold { \underline{\large\pink{Therefore : - }}}} \:$

$\red{\sf{\star\;Length }}$

$\purple{\sf{\star\;X+10}}$

$\green{\sf{\star\;15 + 10 = 25}}$

$\blue{\sf{\star\;Breadth~=~x~=~15}}$

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$\large{\underbrace{\sf{\purple{Explore \: more:}}}}$

⠀

★More Formulas

• Area of rectangle = length × breadth sq.units

• Perimeter of square = 4 × side units

• Area of square = side × side sq.units

• Perimeter of circle = 2πr units

• Area of circle = πr² sq.units

• Perimeter of parallelogram = 2 × (a + b) units

• Area of parallelogram = base × height sq.units

• Perimeter of rhombus = 4 × side units

• Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

• Perimeter of equilateral triangle = 3 × side units

• Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

• Perimeter of trapezoid = (Sum of all sides) units

• Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units

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