Question

The least count of a screw gauge is 0.005 cm. The diameter of a wire is 0.020 cm as measured by it. The percentage error in measurement isA. 25%
B. 20%C. 15%
D. 5%

Answer 1

Answer ⇒ Option (a). 25 %

Explanation ⇒

Given conditions ⇒

Least Count = 0.005 cm.

Diameter of the wire = 0.020 cm.

% Error = Lest count/Measured Diameter × 100

= 0.005/0.020 × 100

= 0.25 × 100

= 25 %

Hence, Option (a). is correct.

Hope it helps.

Answer 2

Answer:

The percentage error in measurement is 25 %

Explanation:

The least count of a screw gauge is 0.005 cm. The diameter of a wire is 0.020 cm as measured by it. The percentage error in measurement is

A. 25%  

B. 20%

C. 15%  

D. 5%

Percentage error in measurement = (Least count / Dimension Measured) * 100

The least count of a screw gauge is 0.005 cm

Dimension Measured = 0.020 cm

Percentage error in measurement = (0.005/0.020) * 100 = 25 %

option A is correct -

The percentage error in measurement is 25 %