Question

The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure 5 micrometer diameter of a wire is

Answer 1

minimum number of division of division scale should be 200.

it is given that,

least count of main scale of a screw guage = 1mm = 10^-3 m

pitch of screw guage = least count of main scale of screw guage = 10^-3 m

diameter of wire = 5 μm

it is clear that, 5μm is much smaller than least count of main scale. for minimum number of division of circular scale,

least count of screw guage = diameter of wire = 5 μm = 5 × 10^-6 m

now,

least count of screw guage = pitch/number of division of circular scale

⇒5 × 10^-3 = 10^-3/N

⇒N = 1000/5 = 200

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Answer 2

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Least count: metre scale = 1 mm, vernier scale = 0.1 mm, screw gauge = 0.01 mm and spherometer = 0.... Mcq: in a micrometer screw gauge, circular scale is marked on: thimble, ratchet, stud or sleeve? The circular scale of a screw guage contains 100 divisions and its pitch is 1mm.