Question

The least cpunt of astop watch is 0.1s. The time of 20 oscillatiins of the pendulum is found to be 30s. The maximum perxentage error in the time period is

Answer 1

$t = 20 \div 30 + or - 0.1$

• %T=0.1÷2/3×100
• =0.3×50
• =15%
• =