Physics, asked by helenamathew043, 6 months ago

The least distance of distinct vision for a

farsighted person is 1m. The optical power of the

lens of his specs which effectively reduces his

LDDV to 25 cm, is :-

(1) +3D

(2) +2D

(3) –3D

(4) None of these​

Answers

Answered by ss5659961
0

Answer:

2 is the answer

Explanation:

please follow me

Answered by 11naveen2006
0

Answer:

None of these​

Explanation:

Because The optical power of the lens of his specs which

effectively reduces his LDDV

Similar questions