Question

The least multiple of 13, which on dividing by 4, 5,
6, 7 and 8 leaves remainder 2 in each case is:
(a) 2520 (b) 842 (c) 2522 (d) 840​

Answer 1

Answer:

option c is right...(2522)

Step-by-step explanation:

we know the divisibility rule of 4..last two digits ....

option a and d are directly divisible...hence these two are wrong..

remaining two ...options are b and c

take first least one...i.e.842..

it satisfy all which get remainder as 2..but it is not a multiple of 13...

hence this is the answer which left...i.e.option C...(2522)