Question

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is ?​

Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

L.C.M. of 6, 9, 15 and 18 is 90.

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

=>Required number = (90 x 4) + 4 = 364.

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Answer 2

Answer:

take LCM of 6,9,15,18.

LCM = 90.

Now go on with adding 4 to each multiples of 90 and checking its divisiblity by 7.

90+4=94 not divisible by 7

180+4=184. not divisible by 7

270+4=274 not divisible by 7

360+4=364 divisible by 7

Hence 364 is the required number

hope this helps you :3