The least multiple of 7,which lives a remainder of 4,when divided by 6,9,15,18
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Answer:
90
Step-by-step explanation:
The LCM of 6, 9, 15 and 18 is 90. So the requires number is of the form 90x + 4 that is a multiple of 7. 91x is divisible by 7, so now 4 - x should be divisible by 7
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