Question

The least no to be. SUbtracted from 743to get a perfect square

Answer 1

$\textbf{To find:}$

$\text{The least number should be subtracted from 743 to get a perfect square}$

$\textbf{Solution:}$

$\text{Clearly, 743 lies between 729 and 784}$

$\text{That is,}729<743<784$

$\implies\sqrt{729}<\sqrt{743}<\sqrt{784}$

$\implies\,27<\sqrt{743}<28$

$\text{Now,}$

$743-14=729=(27)^2$

$\therefore\textbf{14 should be sutracted from 743 to get a perfect square}$

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