Question

the least numben which when
divided by 16,10,20 and 25 leaves
4 as a remainder in each case but
when divided by 7 of leaves no remainder
be​

Answer 1

Answer:

L.C.M. of 16, 18, 20, 25 = 3600

Therefore required number = 3600k+4 which is exactly divisible by 7 for certain value of k. When k = 5

Required number = 3600×5+4 = 18004,

Which is exactly divisible by 7.