the least number of square tiles need to pay the floor of a room 50 M 70 cm long and 9 metre 2 cm wide is
Answers
Answered by
1
Length of the room = 15 m 17 cm = 15 *100 +17 = 1517 cm.
Breadth of the room = 9 m 2 cm = 902 cm.
The HCF of the 1517 and 902 will be size of square tiles.
HCF 1517 and 902 = 41 cm.
Area of the room = length * breadth = 1517 * 902 cm2.
Area of tiles = 41 *41 cm21
So, no. of tiles required = (1517 *902) /(41*41) = 814 tiles.
Breadth of the room = 9 m 2 cm = 902 cm.
The HCF of the 1517 and 902 will be size of square tiles.
HCF 1517 and 902 = 41 cm.
Area of the room = length * breadth = 1517 * 902 cm2.
Area of tiles = 41 *41 cm21
So, no. of tiles required = (1517 *902) /(41*41) = 814 tiles.
Similar questions