the least number of squares tiles that are required to pare exactly a floor of hall of x^8 ×y^6 meters long and x^4×y^4meters wide is
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0
Answer:
Here,
the length of the floor is 9m99cm=999m
the width of the floor is 4m7cm=407m
The area of the floor is therefore (length∗width)=(999∗407)m
2
=406593m
2
Now, for a number of tiles, to completely cover the whole floor, if we divided the whole area by the number of tiles, should give the area of one tile.
On doing so for A, B & D, we get fractional result, which indicates that this number of tiles won't fully cover the floor. For C,
area of one tile is
297
406593
=1369m
2
=37
2
m
2
, which indicates a tile with side 37m
Answered by
0
Answer:
(x^8*y^6)*(x^4*y^4)
=x¹²*x⁸y⁴*y⁶x⁴*y¹⁰
=x²⁴*y²⁰
now you can devide
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