Question

the least number such that, when it divided by 15, 25, 35 and 45. it leaves remainder 7, 17, 27 and 37 respectively is

Answer 1

15-7=8
25-17=8
35-27=8
45-37=8
LCM=1575
The required number =1575-8=1567

Answer 2

Answer:

Required Least Number is 1567.

Step-by-step explanation:

Given Divisors: 15 , 25 , 35 and 45

Respective Remainders: 7 , 17 , 27 , 37

To find: Least Number divided by given divisors and leaves respective remainders.

Clearly from divisors and remainders. Difference between them is 8 in each case.

So, we have to find LCM of the divisors and subtract 8 from them.

15 = 3 × 5

25 = 5 × 5

35 = 5 × 7

45 = 3 × 3 × 5

LCM = 5 × 3 × 3 × 7 × 5 = 1575

Required Number = 1575 - 8 = 1567

Therefore, Required Least Number is 1567.