Question

The least number that is divisible by all the numbers from 1 to 10

(both inclusive) is​

Answer 1

Answer:

2520

We want LCM(1,2,3,4,5,6,7,8,9,10)

We can ignore 1, since any counting number is divisible by 1.

We prime factor each of the counting numbers from 2 to 10

2 = 2

3 = 3

4 = 2*2

5 = 5

6 = 2*3

7 = 7

8 = 2*2*2

9 = 3*3

10 = 2*5

The LCM of all those must have as many factors of

each prime that appears in any factorization

2 appears at most 3 times as a factor of 8

3 appears at most 2 times as a factor of 9

5 appears at most 1 time as a factor if 5 and 10

7 appears at most 1 time as a factor of 7

So the LCM has

3 factors of 2, 2 factors of 3, and 1 facor each of 5 and 7

LCM = 2*2*2*3*3*5*7 = 2520

Answer 2

Answer:

heya mate.....(◍•ᴗ•◍)❤

Step-by-step explanation:

$1 = 1 \times 1 \\ \\ 2 = 2 \times 1 \\ \\ 3 = 3 \times 1 \\ \\ 4 = 2 \times 2 \\ \\ 5 = 5 \times 1 \\ \\ 6 = 2 \times 3 \\ \\ 7 = 7 \times 1 \\ \\ 8 = 2 \times 2 \times 2 \\ \\ 9 = 3 \times 3 \\ \\ 10 = 2 \times 5$

lcm of all these....

$2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 7 = 2520$

so hre 2520 is the least number ...which is divisibleby all the numbers from 1 to 10