Question

the least number which is a perfect square and has 540 as a factor

Answer 1

540 = 2 × 2 × 3 × 3 × 3 × 5,

which is not a perfect square because the numbers of 3 and 5 are not even in numbers

So, we multiply the number by 3 and 5.

Then, we get :

540 × 3 × 5 = 2 × 2 × 3 × 3 × 3 × 3 × 5 × 5

i.e., 8100 = 90²

The required number is 8100.

Answer 2

Answer:

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Step-by-step explanation:

now the answer:

by prime factorisation of 540 we get 540 = 2*2*3*3*3*5

Now we see that 540 is short of 3and five in forming a perfect square therefore we multiply 3*5 to 540 = 8100

Therefore 8100 is the least perfect square which has 540 as a factor.

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