Math, asked by bithi2256, 10 months ago

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

Answers

Answered by Shanaya1312
1

Answer:

Step 1- (12-8),(15-8),(20-8),(54-8)

=4,7,12,46

Step 2- LCM of 4,7,12&46=

4=2^2

7=1*7

12=2^2*3

46=2*23

LCM=2^2*3*7*23=1932

Therefore the required number is 1932

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Answered by sandhyapotlapallijun
0

Answer:

1932

Step-by-step explanation:

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