The least number which when divided by 12,15,20 or 54 leaves in each case a remainder ‘4'?
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Firstly we have to find LCM of 12,15,20 & 54
12=2×2×3
15=3×5
20=2×2×5
54=2×3×3×3
LCM=540
Since it leave 4 as remainder
So,the required no. is 540+4
that is 544
12=2×2×3
15=3×5
20=2×2×5
54=2×3×3×3
LCM=540
Since it leave 4 as remainder
So,the required no. is 540+4
that is 544
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