The least number which when divided by
15, 27, 35 and 42 leaves in each case a remainder 7 is:
a) 18 97 b) 19 87
c) 18 83 d) 20 07
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To Find: A number which when divided by 15, 27, 35 and 42 leaves remainder 7.
Step-by-step explanation:
To find the least number which when divided by 15,27,35 and 42 leaves a remainder 7 is to take Lcm off all the four numbers
There Is a photo at the end Of how to find LCM
LCM (15,27,35,42) = 2 x 3 x 3 x 3 x 5 x 7
LCM (15,27,35,42) = 1890
Now as per the given Information in the question There is always a remainder left that is 7 so we will add 7 to the LCM
So, the number is = 1890 + 7
=1897
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