The least number which when divided by
15, 27, 35 and 42 leaves in each case a remainder 7 is:
a) 18 97 b) 19 87
c) 18 83 d) 20 07
Answers
Answered by
2
Answer:
1897
Step-by-step explanation:
First find the LCM of 15,27,35 and 42 by which ever method you like.
The answer will be 1890.
Then add 7 as the remainder should be 7.
Because Dividend=Divisor*Quotient + Remainder
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