the least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is
Answers
Answered by
31
ANS : 1897
Lcm of (15, 27, 35, 42) =5*3*3*3*7*2=1890
To leave a remainder 7, add 7 to it 1897
Lcm of (15, 27, 35, 42) =5*3*3*3*7*2=1890
To leave a remainder 7, add 7 to it 1897
Answered by
51
Answer:
The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.
Step-by-step explanation:
To find : The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case ?
Solution :
We find the LCM of 15,27,35 and 42.
2 | 15 27 35 42
3 | 15 27 35 21
3 | 3 9 35 7
3 | 1 3 35 7
7 | 1 1 35 7
5 | 1 1 5 1
| 1 1 1 1
In each case it leaves a remainder 7 so we add 7 in the LCM of the numbers.
i.e.1890+7=1897.
Therefore, The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.
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