Question

the least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is

Answer 1

ANS : 1897

Lcm of (15, 27, 35, 42) =5*3*3*3*7*2=1890

To leave a remainder 7, add 7 to it 1897

Answer 2

Answer:

The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.

Step-by-step explanation:

To find : The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case ?  

Solution :  

We find the LCM of 15,27,35 and 42.

2 | 15  27  35  42

3 | 15  27  35  21

3  | 3    9    35  7

3  | 1     3    35   7

7  | 1     1    35   7

5  | 1     1    5    1

   | 1     1     1    1

$LCM(15,27,35,42)=2\times 3\times 3\times 3\times 5\times 7$  

$LCM(15,27,35,42)=1890$  

In each case it leaves a remainder 7 so we add 7 in the LCM of the numbers.

i.e.1890+7=1897.

Therefore, The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.