Question

The least number which when divided by 16, 18 ,20 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder. Answer shortcut trick

Answer 1

let the number be N
N = lcm (16, 18, 20, 25)k + 4
N = 3600k+4
rem (3600k+4)/7 = 0
substitute value of k by trial and error.
When k = 5
we get 18000+4
=18004