Question

The least number which when divided by 35 , 56 and 91 leaves remainder 7 in each case pls fast pa

Answer 1

Answer:

L.C.M. of 35, 56 and 91 = 3640

Required number = x * (3640) + 7

If x = 1

Then the number is 3640 + 7 = 3647

Hence the ans is 3647

Hope it helps mate....

Answer 2

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

Find the LCM of 35, 56 and 91. For that find the factors of

35 = 5x7

56 = 2x2x2x7

91 = 7x13

So the LCM = 2x2x2x7x5x13 = 3640.

The number you want is 3640+7 = 3647.

Check: 3647/35 = 104 + 7 as remainder.

3647/56 = 65 + 7 as remainder.

3647/91= 40 + 7 as remainder.

The answer is 3647.

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