The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :
A. 57
B. 59
C. 61
D. 63
Answers
Answered by
4
Answer:
57
Explanation:
Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3
∴ The required Number = LCM of (4, 5, 6) – 3
= 60 – 3 = 57.
Hence option [A] is correct answer.
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