Question

The least number which when divided by 4 6 8 12 and 16 leaves a remainder of 2 in each case is

Answer 1

hey...hope this will help u...

Answer 2

$Find \: LCM \: of \: 4,6,8,12 \:and \:16$

2| 4,6,8,12,16

___________

2| 2,3,4,6,8

___________

2| 1,3,2,3,4

___________

3| 1,3,1,3,2

___________

***1,1,1,1,2

LCM of 4,6,8,12 and 16 = 2×2×2×3×2 = 48

$\red{ The \: least\: number \:which \:when}\\\red{ divided\: by\: 4, 6 ,8 ,12\: and\: 16 \:leaves\: a}\\\red {remainder\: of\: 2\: in\: each\: case\: is}\\ = LCM \: of \: 4,6,8,12\:and \:16 + Remainder \\= 48 + 2 \\= 50$

Therefore.,

$\red{ Required \:number } \green {= 50}$

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