the least number which when divided by 48 60 72 108 and 140 leaves 38 50 62 98 and 130 as remainders
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Answer: 151110
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(48 - 38) = 10, (60 - 50) = 10, (72 - 62) = 10, (108 - 98) = 10 & (140 - 130) = 10 .
Required number = (L.C.M. of 48, 60, 72, 108, 140) - 10 = 15120 - 10 = 15110
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