The least number which when divided by 8 12 15 and 20 leaves the remainder 1 is
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Hello,
Let the number be x
. So,
X-1 is divisible by 8, 12, 15 and 20
So ,
To find x-1
We need to find the lcm of the above mentioned numbers .
So
Lcm of 8, 12, 15, 20 is
2 |8 12 15 20
5 | 4 6 15 10
2 |4 6 3 2
|2 3 3 1
So ,the lcm is
2 *2 *2 *3 *3 *5 = 360
So ,
The number is 360 +1 = 361
Hope this will be helping you
Let the number be x
. So,
X-1 is divisible by 8, 12, 15 and 20
So ,
To find x-1
We need to find the lcm of the above mentioned numbers .
So
Lcm of 8, 12, 15, 20 is
2 |8 12 15 20
5 | 4 6 15 10
2 |4 6 3 2
|2 3 3 1
So ,the lcm is
2 *2 *2 *3 *3 *5 = 360
So ,
The number is 360 +1 = 361
Hope this will be helping you
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