the least positive integer n such that (2i/1+ i )^n is positive integer is (1) I6 (2)8 (3) 4 (4) 2
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Step-by-step explanation:
Given
the least positive integer n such that (2i/1+ i )^n is positive integer is
- So (2i / 1 + i)^n is positive.
- Rationalizing the denominator we get
- (2i / 1 + i x 1 – i / 1 – i)^n
- (2i (1 – i) / (1 – i^2)^n
- (2i (1 – i) / 1 – (- 1))^n
- (2i (1 – i) / 2)^n
- (1 – i^2)^n
- (i – i^2) ^n
- (i + 1)^n
- Now if n = 2
- (i – i^2)^2 = 1 + i^2 + 2i
- = 2i
- So n = 2 is not satisfied.
- Now if n = 3 we get
- (i – i^2)^3 = (1 + i)^2(1 + i)
- = 2i (1 + i)
- = 2i – 2
- So n= 3 is not satisfied.
- Now if n = 4 is not satisfied as it gives negative value.
- Now if n = 8 we get
- So (i – i^2)^8
- ((i – i^2)^4)^2
- (- 4)^2
- = 16
- Therefore n = 8 is satisfied.
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Answer:
n=8 is the right answer ........ . ....
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