The least positive value of m for which the equation x^2 + mx +4 = 0 has real roots
Answers
Answered by
3
Answer:
The real roots is 4.
Step-by-step explanation:
Here the given equation is,
=> X²+MX+4 = 0
Here
a = 1,b = m, & c =4.
If the equation is supposed to have real roots, then D≥0.
Thus,
m²-4×1×4≥0
m² ≥ 16
m ≥±4
m∈[-∞,-4]∪[4-∞]
Hence, the least positive value of m which the equation has real roots is 4.
Answered by
0
Answer:
m=±4
Step-by-step explanation:
has real roots=b^2 - 4 ac
=m^2 - 16
m=±4
this is the required answer
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