Math, asked by navyasnehil, 6 months ago

The least rationalizing factor of √6 x √27 is *​

Answers

Answered by jaidansari248
1

Answer:

 \frac{ \sqrt{6} }{ \sqrt{27} }  \\  =   \frac{ \sqrt{2 \times 3} }{ \sqrt{ 3 \times 3 \times 3}}  \\  =  \frac{ \sqrt{2} }{ \sqrt{3 \times 3} }  \\  =  \frac{ \sqrt{2} }{ \sqrt{ {3}^{2} } }  =  \frac{ \sqrt{2} }{3}

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