Math, asked by sheelaraj680, 5 months ago

the least square number is called______​

Answers

Answered by divyansh721
0

The minimum of the sum of squares is found by setting the gradient to zero. Since the model contains m parameters, there are m gradient equations:

{\displaystyle {\frac {\partial S}{\partial \beta _{j}}}=2\sum _{i}r_{i}{\frac {\partial r_{i}}{\partial \beta _{j}}}=0,\ j=1,\ldots ,m,}  

∂β  

j

​  

 

∂S

​  

=2  

i

​  

r  

i

​  

 

∂β  

j

​  

 

∂r  

i

​  

 

​  

=0, j=1,…,m,

and since {\displaystyle r_{i}=y_{i}-f(x_{i},{\boldsymbol {\beta }})}r  

i

​  

=y  

i

​  

−f(x  

i

​  

,β), the gradient equations become

{\displaystyle -2\sum _{i}r_{i}{\frac {\partial f(x_{i},{\boldsymbol {\beta }})}{\partial \beta _{j}}}=0,\ j=1,\ldots ,m.}−2  

i

​  

r  

i

​  

 

∂β  

j

​  

 

∂f(x  

i

​  

,β)

​  

=0, j=1,…,m.

The gradient equations apply to all least squares problems. Each particular problem requires particular expressions for the model and its partial derivatives.

A regression model is a linear one when the model comprises a linear combination of the parameters, i.e.,

{\displaystyle f(x,\beta )=\sum _{j=1}^{m}\beta _{j}\phi _{j}(x),}f(x,β)=  

j=1

m

​  

β  

j

​  

ϕ  

j

​  

(x),

where the function {\displaystyle \phi _{j}}ϕ  

j

​  

 is a function of {\displaystyle x}x.

Letting {\displaystyle X_{ij}=\phi _{j}(x_{i})}X  

ij

​  

=ϕ  

j

​  

(x  

i

​  

) and putting the independent and dependent variables in matrices {\displaystyle X}X and {\displaystyle Y}Y we can compute the least squares in the following way, note that {\displaystyle D}D is the set of all data.

{\displaystyle L(D,{\vec {\beta }})=||X{\vec {\beta }}-Y||^{2}=(X{\vec {\beta }}-Y)^{T}(X{\vec {\beta }}-Y)=Y^{T}Y-Y^{T}X{\vec {\beta }}-{\vec {\beta }}^{T}X^{T}Y+{\vec {\beta }}^{T}X^{T}X{\vec {\beta }}}L(D,  

β

​  

)=∣∣X  

β

​  

−Y∣∣  

2

=(X  

β

​  

−Y)  

T

(X  

β

​  

−Y)=Y  

T

Y−Y  

T

X  

β

​  

−  

β

​  

 

T

X  

T

Y+  

β

​  

 

T

X  

T

X  

β

​  

 

Finding the minimum can be achieved through setting the gradient of the loss to zero and solving for {\displaystyle {\vec {\beta }}}  

β

Answered by Jash1029
0

Answer:

We know that the smallest 4 digit number is 1000. But it is not a perfect square number. So, the smallest four digit number which is a perfect square must be near to 1000. Hence, The smallest four digit number which is a perfect square is 1024

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