Math, asked by umith, 1 month ago

The least value of 2sin^2 teta+ 3 cos^2teta is k then k/3 =​

Answers

Answered by nithyashree1577
1

Answer:

Correct option is

B

2

given, 2sin

2

θ+3cos

2

θ

=2−2cos

2

θ+3cos

2

θ

=2+cos

2

θ

Since we know that −1≤cosθ≤1 then 0≤cos

2

θ≤1,

So minimum value of cos

2

θ=0

Hence,minimum value of 2sin

2

θ+3cos

2

θ=2

Answered by kaurparveen9661
3

given, 2sin

2

θ+3cos

2

θ

=2−2cos

2

θ+3cos

2

θ

=2+cos

2

θ

Since we know that −1≤cosθ≤1 then 0≤cos

2

θ≤1,

So minimum value of cos

2

θ=0

Hence,minimum value of 2sin

2

θ+3cos

2

θ=2

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