Math, asked by sreevardhan205, 9 months ago


The least value of 2sin square thita + 3cos square thita is​

Answers

Answered by Anonymous
12

Your Answer:

We have to find the least value of {\tt 2\sin^{2}\theta+3\cos^{2}\theta}

Solving

\tt  {\tt 2\sin^{2}\theta+3\cos^{2}\theta}\\\\=2\sin^{2}\theta+2\cos^{2}\theta+\cos^{2}\theta\\\\=2(\sin^{2}\theta+\cos^{2}\theta)+\cos^{2}\theta\\\\=2(1)+\cos^{2}\theta\\\\=2+\cos^{2}\theta\\\\The\:minimum\:value\:of \:\cos^{2}\theta=0,\: \\\\So,\:putting\: value \:of\: \cos^{2}\theta\\\\=2+0\\\\=2

The minimum value of this is 2.

Answered by Anonymous
8

your answer refer to the attachment.....

  • Explanation

  • using identity sin\theta+cos\theta=1

  • we know cos^2\theta=0
Attachments:
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