The least value of K such that the number 43K4567 is divisible by 11.
2)6,1)4
3)7
4)8
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Answer:
8
The least value of K such that the number 43K4567 is divisible by 11.
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sum of the even place =4+K+5+7=16+K
sum of the odd place=3+4+6=13
Difference=(16+K)-13
=16+K-13=3+K
hence 3+K/11
When K=8
3+8=11
11/11=1
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