Question

The least value of natural number n for which the number (2*2*2*3*75)^n ends with the digit 0 is

2

1

such value of n can't be found

3

​

Answer 1

Answer:

=(2*2*2*3*75)^n

if, n=2 then

ans.3,240,000

so answer is :(2*2*2*3*75)²

Step-by-step explanation:

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