Question

The least value of new for which 1+2+2^2+.....+n terms is greater than 100 is?

Answer 1

Answer:

This is a geometric series

So

(2^n-1)/(2-1)=100

(2^n-1)=100

(2^n-1)=100

2^n-1=100

2^n=100

2^n=101

nlog2=log101

n=log101/log2

n=6.658

n=7

Step-by-step explanation:

First first find n for which sum is100 then take the no. Which is nearest Greater or equal integer from obtained answer.