Question

the least value should be given to y so that the five digit number 637y5 is divisible by 3is ​

Answer 1

least value of Y = 0

Step-by-step explanation:

Given: Five-digit number = 637y5

Let us find out the sum of the digits:

=> 6 + 3 + 7 + y + 5

=> 21 + y

Clearly, 21 is divisible by 3

So, we just add the number with 0

=> 21 + y

=> 21 + 0 {Taking y = 0}

=> 21

Therefore, 21 is divisible by 3 if the least value of y = 0

* Divisibility rule of 3:

If the sum of the digits of the number is divisible by 3, then the number is divisible by 3