The least value that should be added to (x3 – 3x2 + 4x – 13) to obtain a polynomial which is exactly divisible by (x – 3) is
a)1
b)2
c)-2
d)-1
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p(3)=3^3-3*3^2+4*3-13
=27-3*9+12-13
=27-27+12-13
=-1
Therefore,-1 should be added to x^3-3x^2+4x-13 to obtain a polynomial which is exactly divisible by x-3
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