Question

The legs of a right angle triangle are in the ratio 3:4 and it's area is 1014cm².find the length of its cost. ​

Answer 1

we let legs is 3x , 4x  

area = (12 x*2)/2

= 6 x*2

6 x*2 = 1014

x*2 = 169

x = 13  

length of the legs is 39 , 52

Answer 2

$\huge \bf \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}$

$\bf{GIVEN \colon - }$

The sides of right angled triangle I.e. the base and height are in ratio 3:4.

Area = 1014 cm²

$\bf{SOLUTION}$

Let the sides of triangle in ratio be x .

→ 3x and 4x

°•° Area of right angled ∆ is

1

== × base × height

2

Hence ,

$\implies \sf \: \frac{1}{2} \times 3x \times 4x = 1014 \\ \\ \implies \sf \frac{1}{ \cancel{2}} \times 3x \times \cancel{4}x = 1014 \\ \\ \implies \sf 3x \times 2x = 1014 \\ \\ \implies \huge \sf6x^2 = 1014 \\ \\ \implies \huge \sf \: x^2 = \frac{1014}{6} \\ \\ \implies \huge \sf \: x^2= \frac{ \cancel{1014 }}{ \cancel{6}} \\ \\ \implies \huge \bf \: x^2= 169$

$\huge\bf{x=\sqrt{169}}$

$\huge\bf\pink{x=13}$

Hence,

sides are

→ 3x = 3×13

$\bf{39 \: cm}$

and,

→ 4x = 4×13

$\bf{52 \: cm}$