the legs of a right Triangle are in ratio 3 : 4 and its area is is 101 4 CM square. Find its hypotenuse
Answers
Correct Question:
The length of two short sides of a right Triangle is in ratio 3:4 and its area is 1014 CM square. Find its hypotenuse.
Solution:-
Given:
- The ratio of two short sides of the right triangle is 3:4
- The area of the right-angled triangle is 1014 cm sq.
Let, the side i.e Base be 3x cm
And Perpendicular (height) be 4x cm
- Area of the triangle = 1014 cm sq.
∴ x = 13
So, Base = 3x = 39cm
And Perpendicular(height) = 4x = 52cm
So, by using Pythagoras theorem,
⇒ Hypotenuse² = (39)² + (52)²
⇒ Hypotenuse² = 1521 + 2704
⇒ Hypotenuse² = 4225
⇒ Hypotenuse =
⇒ Hypotenuse = 65cm
Hence,
The Hypotenuse of the right-angled triangle is 65cm.
Figure :- Refers to the attachment
✴ The legs of a right triangle are in ratio 3 : 4 and its area is is 1014 cm². Find its hypotenuse.
➡ The hypotenuse of Triangle is 65 cm.
Given :-
- The legs of a right triangle are in ratio 3 : 4.
- The area of triangle is 1014 cm².
To Find :-
- The hypotenuse of Triangle.
Calculation :-
Let the leg of the triangle be x
So it's sides 3:4 are equal to 3x and 4x .
According to the question,
We know the, Area of right angle triangle = ×base×hieght.
➝ 1014 = × 3x × 4x
➝ 1014 × 2 = 3x × 4x
➝ 2028 = 12x²
➝ = x²
➝ x² =
➝ x² = 169
➝ x =
➩ x = 13 cm
Using x finding the sides of triangle,
- 3x = 3×13 = 39
- 4x = 4×13 = 52
Here , We have a right triangle,applying Pythagoras theorem.
✒ Pythagoras theorem states the sum of the square of two sides namely, perpendicular & base is equals to the square of its hypotenuse.
➤ Hypotenuse ² = P² + B²
➠ Hypotaneuse² = 39² + 52²
➠ Hypotaneuse² = (39×39) + (52×52)
➠ Hypotaneuse² = 1521 + 2704
➠Hypotaneuse =
➙ Hypotaneuse = 65 cm.
⍈ Hence, The hypotenuse of the triangle is 65 cm.
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