Question

the legs of a right triangle are in the ratio 3:4 and it's area is 600cm sq. find the lengths of its legs.

Answer 1

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Let the legs be 3x and 4x resp.
Lets assume that 4x is the base.
Then height is 3x.
Ar. of Δ=1/2*bh= 1/2 * 3x*4x
ar.= 6x^2
600=6x^2
x^2=100
x=√100=10
thus, 3x=30cm and 4x =40cm...

........................ Hope this helps...
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Answer 2

I am not sure it is