the legs of a right triangle are in the ratio 3:4 and its area is 1014 CM square find its hypotenuse
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I didn't understood from where did your triangle got legs
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Let the 2 sides of the triangle be 3x and 4x.
area of a triangle = 1/2*base*height
1014 = 1/2*3x*4x
1014 = 3x*2x
1014 = 6xsquare
1014/6 = x square
169 = x square
There fore,
x = 13 cm
thus,
3x = 3*13 = 39
4x = 4*13 = 52
let hypotenuse be 'a' (pythogorus theorem)
(a)2 = (39)2 + (52)2
a =
a =
a = 52.374(approx)
Hope it helps you...
area of a triangle = 1/2*base*height
1014 = 1/2*3x*4x
1014 = 3x*2x
1014 = 6xsquare
1014/6 = x square
169 = x square
There fore,
x = 13 cm
thus,
3x = 3*13 = 39
4x = 4*13 = 52
let hypotenuse be 'a' (pythogorus theorem)
(a)2 = (39)2 + (52)2
a =
a =
a = 52.374(approx)
Hope it helps you...
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