The legs of an isosceles triangle have lengths x + 1 and -x + 7 . The base has length 3x - 3. What is the length of the base?
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Answered by
8
BtQ,
x+1=-x+7
2x= 8
x= 4
.•. The base is 3*4-3= 9
x+1=-x+7
2x= 8
x= 4
.•. The base is 3*4-3= 9
Answered by
6
The legs of the given isosceles triangle are x+1 & -x+7
These legs are equal as the type of triangle is isosceles triangle.
So,
x+1 = -x+7
x+x=7-1
2x=6
x=6/2
x=3 ............................(1)
The base has length 3x-3
...............................(given )
The length of base =3x-3
=3(3)-3 ................... from (1)
=9-3
=6
Therefore,
The length of the base is 6units.
hope this helps ! ! !#
These legs are equal as the type of triangle is isosceles triangle.
So,
x+1 = -x+7
x+x=7-1
2x=6
x=6/2
x=3 ............................(1)
The base has length 3x-3
...............................(given )
The length of base =3x-3
=3(3)-3 ................... from (1)
=9-3
=6
Therefore,
The length of the base is 6units.
hope this helps ! ! !#
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