the legs of right angle triangle are in ratio 34 and its area is 1014 CM square find the length of its legs
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let the sides be 3x,4x
area =1*3x*4x/2=6xsq.
given area=1014 cm 2
6x sq.=1014
x sq.=1014/6
x sq.=169
x=13 cm
one side=3*13=39 cm
second side=4*13=52 cm
area =1*3x*4x/2=6xsq.
given area=1014 cm 2
6x sq.=1014
x sq.=1014/6
x sq.=169
x=13 cm
one side=3*13=39 cm
second side=4*13=52 cm
knavsharan:
thanks
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