Question

The legth breadth and height are 4.5 m , 3 m , 350 m find the cost of a room plastering at rs 8 per m square

Answer 1

Here your answer goes

Step :- 1

We know that Total Surface area ( TSA )

= >> 2 ( lb +bh + lh )

Step :- 2

==> $2(4.5* 3 + 3* 3.5 + 4.5 * 3.5)$

==> $2(13.5+10.5+15.75)\\=2(39.75)\\=79.5 m^2$

Step :- 3

Given ,

$1m^{2} = Rs. 8$

$79.5m^{2} * 8$

===>  Rs. 636

→→ Be BRAINLY ←←←

Together We go far

Answer 2

Total surface area = 2(lb+bh+hl)

Putting values

Total surface area= 2(4.5×3 + 3×350 + 350×4.5)

=2638.5

Cost of 1m^2=rupee8

2638.5 cost = 8×2638.5

=21108 rupee

@skb