the lenght of a conductor is halved keeping its thickness unchanged.its resistance is
a) doubled
b) halved
c) tripled
d) unchanged
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If length is doubled and radius is halved the resistance would increase by 8 times. Since R = P* L/A: since resistivity is constant, Length becomes 2L and area becomes 1/4 th. Therefore it is 8 times. Originally Answered: How does the resistance of a wire change if its length is doubled and its radius is halved?
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