Question

the lenght of a parallelogram PQRS is 14 units and the height of the parallelogram is 10 units what is area of truangle QPR​

Answer 1

Answer:

Given: SR=12cm, QM=7.6cm, PS=8cm.

Area of parallelogram=base×height

=12×7.6=91.2cm

2

.

Area of parallelogram=base×height

⇒91.2=8×QN

⇒QN=

8

91.2

=11.4cm.

Answer 2

$\large \bold{ \color{purple}{ \colorbox{orange}{answer}}}$

$\large{ \sf{Given}}$

SR=12cm, QM=7.6cm, PS=8cm

$\large{ \red{\{ \overline{area \: of \: parallelogram = base \times height}}}$

$\large{12 \times 7.6 = 91.2 {cm}^{2} }$

Area of parallelogram=base×height

$\large \purple{ \implies{91.2 = 8 \times qn}}$

$\large{ \orange {\implies{qn = \frac{91.2}{8} = 11.4cm}}}$

hope its help u