Question

The lenght of a plot is twice its breadth. Its area is 4050 sq.m. Find the cost of the fencing the plot at Rs 2.50 meter??

Answer 1

112.5 is the answer

Answer 2

Answer:

Rs.675

Step-by-step explanation:

Let the breadth of the plot be x

Now we are given that The length of a plot is twice its breadth.

So, Length of plot = 2x

Now Area of plot = $Length \times Breadth$

Area of plot = $2x  \times x$

Area of plot = $2x^2$

We are given that Its area is 4050 sq.m.

So,  $2x^2=4050$

 $x^2=\frac{4050}{2}$

 $x=\sqrt{\frac{4050}{2}}$

 $x=45$

So, Breadth = 45 m

Length = 2 * 45 = 90 m

Perimeter of Plot = $2(l+b)=2(90+45)=270 m$

Cost of fencing 1 m = Rs.2.50

Cost of fencing 270 m = $2.50  \times 270 = 675$

Hence the cost of fencing the plot is Rs.675