Question

The lenght of a rectangle exceeds its widthby 5m. If the width is increased by 1m and the lenght os decreased by 2m,the area of the new rectangle is 4sq.m less than the area of the original rectangle. Find the dimensions of the original rectangle.

Answer 1

Let the width be x
Old area x(x+5)
New area (x+1)(x+5-2)
Difference in area =4
x(x+5)-(x+1)(x+3)=4
x=7
Dimensions= 7 and 12

Answer 2

Hey there! ☺☻☺

Let the width of rectangle be x.
Then it's length = x+5 
Area of rectangle = l*b = x*(x+5) = (x² + 5x) m²

Now,
New width = x + 1
New length =  x+5 - 2 = x + 3
Area = l*b = x+1 * (x+3) = (x² + 4x + 3) m² 

ATQ,
⇒ (x² + 5x) - (x² + 4x + 3) = 4
⇒ x - 3 = 4
⇒ x = 7

Hence, Original width = x = 7 m
Original length = x + 5 = 12 m

Hope It Helps You! ☺☻☺