Question

the lenght of a rectangle exceeds the width by 14 cm perimetre of rectangle is 160 cm find lenght and width of the rectangle

Answer 1

Answer:

Length of the rectangle is 47cm

Breadth of the rectangle is 33cm

Step-by-step explanation:

Let the length of the rectangle be L

and the breadth of the rectangle be B

According to the condition given in the question,

L = B + 14

We know  that the perimeter of a rectangle = 2(L+B)

Given that the perimeter = 160cm

On substituting the values, we get

160 = 2(L + B)

=> 160 = 2(B + 14 + B)                (as L = B + 14)

=> 160 = 2(2B + 14)

=> 160 = 4B + 28

=> 160 - 28 = 4B

=> 132 = 4B

=> 132/4 = B

=> 33 = B

Therefore, Breadth of the rectangle is 33cm

We know L = B + 14

=> L = 33 + 14

       = 47

Therefore, Length of the rectangle is 47cm

Answer 2

Answer:

length =47cm and width =33cm

Step-by-step explanation:

According to the information provided in the question it is given as

width= w= x

l=x+14

Perimeter  =P= 160cm

We need to find the  length and width of rectangle

Now by applying formula of perimeter of rectangle we get the answer

P=2(l +W)

$160=2(x + x+ 14)\\160=2(2x+14)\\160=4x+28\\4x=160-28\\4x=132\\x=\frac{132}{4}$

Converting to lowest term

$x=33cm$

Now

w=x=32cm

L= X+14

L=32+14

  =47cm

Hence finally concluded that length =46cm and width =33cm